Optimal. Leaf size=136 \[ \frac{\sin (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{6 b}+\frac{5 \sin (a+b x) \sqrt{\sin (2 a+2 b x)}}{16 b}-\frac{5 \sin ^{\frac{3}{2}}(2 a+2 b x) \cos (a+b x)}{24 b}-\frac{5 \sin ^{-1}(\cos (a+b x)-\sin (a+b x))}{32 b}-\frac{5 \log \left (\sin (a+b x)+\sqrt{\sin (2 a+2 b x)}+\cos (a+b x)\right )}{32 b} \]
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Rubi [A] time = 0.0913343, antiderivative size = 136, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.15, Rules used = {4301, 4302, 4306} \[ \frac{\sin (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{6 b}+\frac{5 \sin (a+b x) \sqrt{\sin (2 a+2 b x)}}{16 b}-\frac{5 \sin ^{\frac{3}{2}}(2 a+2 b x) \cos (a+b x)}{24 b}-\frac{5 \sin ^{-1}(\cos (a+b x)-\sin (a+b x))}{32 b}-\frac{5 \log \left (\sin (a+b x)+\sqrt{\sin (2 a+2 b x)}+\cos (a+b x)\right )}{32 b} \]
Antiderivative was successfully verified.
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Rule 4301
Rule 4302
Rule 4306
Rubi steps
\begin{align*} \int \cos (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x) \, dx &=\frac{\sin (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{6 b}+\frac{5}{6} \int \sin (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x) \, dx\\ &=-\frac{5 \cos (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x)}{24 b}+\frac{\sin (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{6 b}+\frac{5}{8} \int \cos (a+b x) \sqrt{\sin (2 a+2 b x)} \, dx\\ &=\frac{5 \sin (a+b x) \sqrt{\sin (2 a+2 b x)}}{16 b}-\frac{5 \cos (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x)}{24 b}+\frac{\sin (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{6 b}+\frac{5}{16} \int \frac{\sin (a+b x)}{\sqrt{\sin (2 a+2 b x)}} \, dx\\ &=-\frac{5 \sin ^{-1}(\cos (a+b x)-\sin (a+b x))}{32 b}-\frac{5 \log \left (\cos (a+b x)+\sin (a+b x)+\sqrt{\sin (2 a+2 b x)}\right )}{32 b}+\frac{5 \sin (a+b x) \sqrt{\sin (2 a+2 b x)}}{16 b}-\frac{5 \cos (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x)}{24 b}+\frac{\sin (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{6 b}\\ \end{align*}
Mathematica [A] time = 0.357032, size = 98, normalized size = 0.72 \[ \frac{\frac{2}{3} \sqrt{\sin (2 (a+b x))} (14 \sin (a+b x)-3 \sin (3 (a+b x))-2 \sin (5 (a+b x)))-5 \left (\sin ^{-1}(\cos (a+b x)-\sin (a+b x))+\log \left (\sin (a+b x)+\sqrt{\sin (2 (a+b x))}+\cos (a+b x)\right )\right )}{32 b} \]
Antiderivative was successfully verified.
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Maple [B] time = 61.386, size = 199880296, normalized size = 1469708.1 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \cos \left (b x + a\right ) \sin \left (2 \, b x + 2 \, a\right )^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 0.572508, size = 806, normalized size = 5.93 \begin{align*} -\frac{8 \, \sqrt{2}{\left (32 \, \cos \left (b x + a\right )^{4} - 12 \, \cos \left (b x + a\right )^{2} - 15\right )} \sqrt{\cos \left (b x + a\right ) \sin \left (b x + a\right )} \sin \left (b x + a\right ) - 30 \, \arctan \left (-\frac{\sqrt{2} \sqrt{\cos \left (b x + a\right ) \sin \left (b x + a\right )}{\left (\cos \left (b x + a\right ) - \sin \left (b x + a\right )\right )} + \cos \left (b x + a\right ) \sin \left (b x + a\right )}{\cos \left (b x + a\right )^{2} + 2 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) - 1}\right ) + 30 \, \arctan \left (-\frac{2 \, \sqrt{2} \sqrt{\cos \left (b x + a\right ) \sin \left (b x + a\right )} - \cos \left (b x + a\right ) - \sin \left (b x + a\right )}{\cos \left (b x + a\right ) - \sin \left (b x + a\right )}\right ) - 15 \, \log \left (-32 \, \cos \left (b x + a\right )^{4} + 4 \, \sqrt{2}{\left (4 \, \cos \left (b x + a\right )^{3} -{\left (4 \, \cos \left (b x + a\right )^{2} + 1\right )} \sin \left (b x + a\right ) - 5 \, \cos \left (b x + a\right )\right )} \sqrt{\cos \left (b x + a\right ) \sin \left (b x + a\right )} + 32 \, \cos \left (b x + a\right )^{2} + 16 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) + 1\right )}{384 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \cos \left (b x + a\right ) \sin \left (2 \, b x + 2 \, a\right )^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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